Question

if x=4/3 is a root of the polynomial f(x)=6x^2-11x^2+kx-20,find the value of k

Answer 1

6* 16/9 - 11* 16/9 + 4/3k - 20 = 0
96/9 - 176/9 + 4/3k - 20 = 0
4/3k = 180/9 + 176/9 - 96/9 = 260/9
4k = 260/3
k = 260/12 = 130/6 = 65/3

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Answer 2

Hey.....!!! here is ur answer......☺️☺️☺️

Here....... Given that,

x = 4/3 is the root of the given polynomial.................6x²–11x+kx–20

When we put the x = 4/3 then the solution of this polynomial will be 0.

then according to the question......

6(4/3)²–11×4/3+k×4/3–20 = 0

6×16/9–44/3+4k/3–20 = 0

96/9–44/3+4k/3–20 = 0

On taking LCM...

(96–132+12k–180)/9 = 0

12k–216 = 0

12k = 216

k = 18 <<<<<<<<<<<<<Ans.

I hope it will help you........✌️✌️✌️