If x=4/3 is a solution of kx^2 - 7x + 4 = 0, then k is
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Answered by
0
Answer:
Since, 2 is root of kx
2
−7x+6=0
⇒k(2)
2
−7×2+6=0
⇒4k−14+6=0
⇒4k=8
⇒k=2
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Answered by
5
Put the value we got
K(4/3)^2-7(4/3)+4=0
K(16/9)-28/3+4=0
K(16/9)-16/3=0
So k=3
K(4/3)^2-7(4/3)+4=0
K(16/9)-28/3+4=0
K(16/9)-16/3=0
So k=3
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