Question

If x=4/3 is a zero of the polynomial. P(x)=6x^3-11x^2+Kx_20 ,find the value of K.​

Answer 1

k = 19

Step-by-step explanation:

6(4/3)^3 -11(4/3)^2 + k(4/3)-20

6(64/27) - 11(16/9) + 4/3k -20

384/27 - 176/9 + 4/3k = 20

384-528/27 + 4/3k = 20

-144/27 + 4/3k = 20

4/3k = 20/1+144/27

4/3 k = 540+144/27

4/3 k = 684/27

k = 684/27 * 3/4

k= 171/9

k = 19

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