Question

if x=4/3 is √ root of the polynomial p(x)=6a³-11x²+9x-20 find the value of a

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

On putting the value of root of a polynomial into that polynomial we get 0

so, 6(4/3)^3-11(4/3)^2+k4/3-20=0

→128/9-176/9+k4/3 -20=0

→-48/9+k4/3 -20=0

→-16/3+k4/3 -20=0

→(4k-16)/3=20

→4k-16=60

→4k=76

→k=19