if x=4/3 is the zero of 6x cube - 11x square + kx - 20 find the value of k
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6x^3 - 11x^2 + Kx -20 =0
putting the value of x=4/3
6(4/3)^3 - 11(4/3)^2 + k 4/3 - 20=0
therefore,
14.22-19.55+4k/3-20=0
this implies,
k=11.0025
or11 (aprox)
hope it will hel U
putting the value of x=4/3
6(4/3)^3 - 11(4/3)^2 + k 4/3 - 20=0
therefore,
14.22-19.55+4k/3-20=0
this implies,
k=11.0025
or11 (aprox)
hope it will hel U
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