If x = 4 - √3 then find √x - 1/√x
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x = 7+4√3
To find √x we proceed,
√x = √(7+4√3)
√x = √(7+2x2√3)
√x = √(7+2√3x4)
√x = √(3+4+2√3x4)….. {writing 7 = 3+4}
If we observe RHS of √x we observe form of
√(a² + b² +2ab) where a=√3 and b =√4
Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3
√x = 2+√3
1/√x = 1/(2+√3)
Multiplying both numerator and denominator by 2 - √3, we get
1/√x = (2-√3)/(2-√3)(2+√3) = (2-√3)/(2²-√3²) =
1/√x = 2-√3
Hence √x -1/√x = 2+√3 -2+√3 = 2√3
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