if x-4=√3y is written in the standard form ax+by+c=0 then find the value of a,b,c
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Answered by
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Answer : Step-by-step explanation : x-4=root 3y ax+by+c=0 x-root 3y-4=0 a=1,,,,b=(-root 3),,,,c=(-4)
Answered by
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The values of a = 1,b= -√3 and c = -4
Given:
x-4 =√3y
To Find:
The value of a, b, and c
Solution:
The equation is a linear equation with two variables. The linear equation is an equation in which the power of the variable is always 1.
The standard form of linear equation with two variables is ax +by +c =0
where a, and b are coefficients of variables x and y. c is constant.
x-4 =√3y
x - √3y - 4 =0
This is of the form ax + by +c=0
∴ a = 1,b= -√3 and c = -4
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