If (x - 4) and (x - 1/4) are both factors of ax2 + 5x + b, show that a = b.
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Since, x-4and x-1/4 are the factors of ax2 +5x+b. ax2 +5x+b=(x-4) (x-1/4)
Or, ax2 +5x+b=x (x-1/4) -4(x-1/4)
or, ax2 +5x+b= x^2-1/4x-4x+1
comparing both sides,
we get,
a=1,
b=1
so, a=b
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