Question

If x = 4 and x = 6 are the solutions of equation 6x2 – 4mx + 4n = 0, find m and n.

Answer 1

Answer:

I think your question is wrong because how can we know which x value we have to put in which number

Answer 2

Answer:

The value of x are 4 and 6

Put x=4

6(4)²-4(4)m+4n

96-16m+4n

taking common

4{24-4m+n}

24 -4m + n =0----------------------- EQ.1

Now,

Put x=6

6(6)²-4(6)m+4n

216-24m+4n

Taking common

4(54-6m+n)

54-6m+n =0------------------------------ EQ.2

SOLVE EQ.1 AND EQ.2

By elimination method

Subtract EQ.1 from EQ.2

(54-6m+n) - ( 24-4m+n) =0

54-6m+n-24+4m-n=0

30-2m=0

2m=30

m=15

Put the value of m in any equation EQ.1 or EQ.2

Put m=15 in EQ.1

24-4m+n=0

24-4(15)+n=0

24-60+n=0

n= 36