Question

If x=4 and y=2 what is the value of x^2+3y/xy
​

Answer 1

Answer:

x=4 and y=2

x^2+3y/xy

So,

4^2 + 3(2)/(4)(2)

16 + 6/8

16 + 3/4

(16×4)/4 + 3/4

64/4 + 3/4

67/4

Answer 2

Answer:

${x}^{2} + \frac{3y}{xy} \\ = {4}^{2} + \frac{3 \times 2}{4 \times 2} \\ = 16 + \frac{3}{4} \\ = \frac{64 + 3}{4} \\ = \frac{67}{4}$

please follow and like me