Question

If x^4+ax^3+bx^2+cx+d=(x^2+px+q) then a)2q=b-a^2/4 b)p-a^2/4=2c c)qa=c d)b-a^2/4=c/a​

Answer 1

Answer:

As we know that for the quadratic equation ax

2

+bx+c=0, roots will be equal if

D=B

2

−4AC=0

Therefore, for the equation,

a(b−c)x

2

+b(c−a)x+c(a−b)=0

A=a(b−c),B=b(c−a),C=c(a−b)

D=0

B

2

−4AC=0

(b(c−a))

2

−4(a(b−c))(c(a−b))=0

⇒ab+bc=2ac

Hence a,b and c are in HP.

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

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