Question

If x=4, find the value of: x=x++ + ++x + 7

Answer 1

$\textsf{\large{\underline{Solution}:}}$

Given:

> x = 4

On evaluating the given expression, we get:

> x = x++ + ++x + 7

> x = 4 + ++x + 7   [x remains 4, pre-increment]

> x = 4 + ++x + 7   [x becomes 5]

> x = 4 + 6 + 7  [x becomes 6, pre-increment]

> x = 17

Therefore:

$\rm:\longmapsto x=17\ \ (Answer)$

$\textsf{\large{\underline{Learn More}:}}$

There are two types of increment/decrement operations.

1. Post increment/decrement.
2. Pre increment/decrement.

Post Increment/Decrement: Here, operation takes place first and then the value is incremented/decremented.

Example:

> int a = 2;

> int b = a++;

> b = 2

Now, a = 3.

Pre Increment/Decrement: Here, value is first increment/decrement and then the operation is carried out.

Example:

> int a = 2;

> int b = ++a;

> b = 3

Also, a = 3