If x=4 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.
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Answer:
k=5/4
Step-by-step explanation:
Let
p(x) = x²-2kx-6=0
x= 4 is one root of the quadratic equation
Remainder = p(4) = 0
=> p(4)=0
=> (4)²-2k(4) - 6 = 0
=> 16-8k-6=0
=> -8k=6-16
=> - 8k = -10
=> k=10/8
=> k=5/4
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