Physics, asked by devyanshsingh1511, 10 months ago

if x=(4-root15),find the value of (+1/x)​

Answers

Answered by TrickYwriTer
5

Explanation:

 \bold{Correct \:  Question -} \\   \\  If \: x = 4 -  \sqrt{15} \:  then \: find \: the \:   value \: of \: x +  \frac{1}{x}

 \bold{Given -  } \\ </p><p> x = 4 - \sqrt{15}  \\  \\  \bold{To \: find - } \\  Value \: of \: x +  \frac{1}{x}  \\  \\ \leadsto (4 -  \sqrt{15} ) +  \frac{1}{(4 -  \sqrt{15} )}  \\ \\   \leadsto\frac{(4 -  \sqrt{15}) {}^{2}   + 1}{(4 -  \sqrt{15}) }  \\ \\  \leadsto\frac{16 - 8 \sqrt{15}  + 15 + 1}{(4 -  \sqrt{15}) }  \\ \\  \leadsto \frac{32 - 8 \sqrt{15} }{(4 -  \sqrt{15}) } \\   \\  \leadsto\frac{8 \cancel{(4 -  \sqrt{15})} }{ \cancel{(4 -  \sqrt{15} )}}  \\  \\   \bold{= 8  }

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