Question

if (x+4)(x+1)-(x-1)(x-2)=0 find the value of x

Answer 1

Questions:-(x+4)(x+1)-(x-1)(x-2)=0
Solution:-
$( {x}^{2} + x + 4x + 4) - ( {x}^{2} - 2x - x + 2)$
$( {x}^{2} + 5x + 4) - ( {x}^{2} - 3x + 2)$
${x}^{2} + 5x + 4 - {x}^{2} - 3x + 2$
2x+6=0
x= -3

Answer 2

Answer:

-1/4

Step-by-step explanation:

(x²+4x+X+4)+(-x²+2x+x-2)

x²-x²+4x+2x+X+X+4-2

6x+2x+2=0

8x = (-2)

X = (-1/4)