Question

if x(4-x)=4, then find the value of x3(x4-14)​

Answer 1

${\huge\star{\mathfrak{\underline{\underline{Answer :}}}}}$

B). 16 (Is the correct answer)

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Answer 2

$\huge\bigstar\mathfrak\darkred{\underline{\underline{SOLUTION:}}}$

Given,

$= > x(4 - x) = 4 \\ = > 4x - {x}^{2} = 4 \\ = > - {x}^{2} + 4x - 4 = 0 \\ = > - {x}^{2} + 2x + 2x = 0 \: \: (factorise)\\ = > x( - x + 2) + 2( - x + 2) = 0 \\ = > ( - x + 2)(x + 2) = 0 \\ = > - x + 2 = 0 \: \: or \: \: x + 2 = 0 \\ = > - x = - 2 \: or \: x = - 2 \\ = > x = 2 \: \: or \: x = - 2$

Putting the value of x=2 in this equation

$= > {x}^{3} ( {x}^{4} - 14) \\ = > {2}^{3} ( {2}^{4} - 14) \\ = > 8(16 - 14) \\ = > 8(2) \\ = > 8 \times 2 \\ = > 16$

hope it helps ☺️