If x=4,y=3 and z=-2,find the value of x^2+y^2+z^2+2xyz
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Answered by
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hey mate here's ur ans ↓↓
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Given, x. = 4, y. = 3 , z = -2
Now , x² + y² + z² + 2XYZ
=(4)²+(3)²+(-2)²+2×4×3×(-2)
=16+9+4-48
=-19
※※※※※※※※※※※※※※※
hope it helps u☺☺✌
※※※※※※※※※※※※※※※※
Given, x. = 4, y. = 3 , z = -2
Now , x² + y² + z² + 2XYZ
=(4)²+(3)²+(-2)²+2×4×3×(-2)
=16+9+4-48
=-19
※※※※※※※※※※※※※※※
hope it helps u☺☺✌
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