Question

if x= 4, y= 3 and z= -2, find the value of x cube + y cube + z cube+ 3xyz​

Answer 1

Answer:

2 is only even number which is prime number.

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Answer 2

✬ The value of x³ + y³ + z³ - 3xyz is 165✬

Step-by-step explanation:

Given values: x = 4, y = 3 and z = -2

To find: Value of x³+y³+z³-3xyz

Solution:

Putting the values,

$\\ :\implies\sf{ {x}^{3} + {y}^{3} + {z}^{3} - 3xyz = 0} \\ \\ :\implies\sf{ {(4)}^{3} + {(3)}^{3} + { (- 2)}^{3} - 3(4)(3)( - 2) = 0 } \\ \\ :\implies\sf{64 + 37 + ( - 8) - ( - 72) = 0} \\ \\ :\implies\sf{64 + 37 - 8 + 72 = 165}$

• Hence,The value of x³+y³+z³-3xyz is 165.