Question

if x = 4, y = 3, z = -2, find the value of x^3 + y^3 + z^3 - 3xyz

Answer 1

I think the answer is
Given,
x=4,y=3,z=-2
x^3+y^3+z^3-3xyz=?
=(x-y)^3+(y-z)^3+(z-x)^3
=(4-3)^3+(3-(-2))^3+(-2-4)^3
= 1^3+5^3+(-6)^3
= 1+125+-216
= 126-216
= -90
OR
I think the answer is
4^3+3^3+(-2)^3-3(4×3×-2)
64+27+(-8)-3(-24)
91-8+72
163-8
=155