Question

If x 4 y 5 z is exactly divisible by 9 then the least value of (x+y+z)

Answer 1

for any number to be divisible by 9 , sum of all of its digit should also be divisible by 9

sum of all digits = x + 4+ y + 5 + z = 9 + x + y + z

now x + y+ z should be such that it total sum should be divisible by 9. putting minimum value of x,y and z as 0

sum = 9 + 0 +0+0= 9 which is divisible by 9 so least value of

x+y+z = 0

number becomes now

04050

now as first digit is 0 . if want want first digit to be greater than 0 so x must be 1 to 9.

and now least value of x+y+z must be 9 so

2nd solution is

x +y+z = 9 if we want x > 0

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