Math, asked by anujrawat805, 1 year ago

if x^40+x^51+5 is divisible by x+1 then find the remainder​

Answers

Answered by siddhitpramanik
5

Answer:

When (x^40)+(x^51)+5 is divided by x+1,

By remainder theorem,

Remainder = p(-1)

= (-1)^40 + (-1)^51 + 5

= 1 + (-1) + 5

= 6-1

= 5

Hope it helps.

Answered by kowshikvkowshik
4

Answer:

5

Step-by-step explanation:

let p(X) be x^40+x51+5. zero of X+1 is-1

p(-1)=(-1)^40+(-1)^51+5

=1+(-1)+5

=5

therefore the remainder when p(X) is divided by X+1 is 5

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