if x^40+x^51+5 is divisible by x+1 then find the remainder
Answers
Answered by
5
Answer:
When (x^40)+(x^51)+5 is divided by x+1,
By remainder theorem,
Remainder = p(-1)
= (-1)^40 + (-1)^51 + 5
= 1 + (-1) + 5
= 6-1
= 5
Hope it helps.
Answered by
4
Answer:
5
Step-by-step explanation:
let p(X) be x^40+x51+5. zero of X+1 is-1
p(-1)=(-1)^40+(-1)^51+5
=1+(-1)+5
=5
therefore the remainder when p(X) is divided by X+1 is 5
Similar questions