Question

if x=√42+√42+√42+√42+...∞ and y=√132+√132+√132+√132...∞ then the value of xy is ?

Answer 1

Answer:

Correct option is

=x (say)

Squaring

42+

42+

42+....∞

=x

2

⇒x

2

=42+x

⇒(x−7)(x+6)=0⇒

x=7,−6

As x>0⇒

x=7