Math, asked by poketglaksh, 5 months ago

If x = 4a2 + b2 - 6ab, y = 3b2 - 2a2 + ab and z = 6a2 + 8b2 - 6ab, find x + y + z



please help me ​

Answers

Answered by singhaniket637
1

x+y+z

4a2+b2+-6ab+3b2-2a2+ab+6a2+8b2-6ab

8a2+12b2-11ab is the answer

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