if x=4by3 is a root of the polynomial 6x^3-11x^2+kx-20 find k
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THERE IS YOURS SOLUTION
◆ So, the value of K is -19.
HOPE IT HELPS
◆ So, the value of K is -19.
HOPE IT HELPS
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Answered by
1
Hiii friend,
X = 4/3
P(X) = 0
P(4/3) = 0 Because 4/3 is a zero of the polynomial 6X³-11X²+KX-20.
Therefore,
P(4/3) => 0
6 × (4/3)³ - 11 × (4/3)² + K × 4/3 - 20 = 0
6 × 64/27 - 11 × 16/9 + 4K/3 - 20 = 0
2 × 64/9 - 176/9 + 4K/3 -20 = 0
128/9 - 176/9 + 4K/3 -20 = 0
128 - 176 + 12K - 180 /9 = 0
128 - 176 + 12K - 180 = 0 × 9
128 - 356 + 12K = 0
-228 + 12K = 0
12K = 228
K = 228/12
K = 19
HOPE IT WILL HELP YOU..... :-)
X = 4/3
P(X) = 0
P(4/3) = 0 Because 4/3 is a zero of the polynomial 6X³-11X²+KX-20.
Therefore,
P(4/3) => 0
6 × (4/3)³ - 11 × (4/3)² + K × 4/3 - 20 = 0
6 × 64/27 - 11 × 16/9 + 4K/3 - 20 = 0
2 × 64/9 - 176/9 + 4K/3 -20 = 0
128/9 - 176/9 + 4K/3 -20 = 0
128 - 176 + 12K - 180 /9 = 0
128 - 176 + 12K - 180 = 0 × 9
128 - 356 + 12K = 0
-228 + 12K = 0
12K = 228
K = 228/12
K = 19
HOPE IT WILL HELP YOU..... :-)
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