Question

if x=4by3 is a root of the polynomial 6x^3-11x^2+kx-20 find k

Answer 1

THERE IS YOURS SOLUTION

◆ So, the value of K is -19.

HOPE IT HELPS

Answer 2

Hiii friend,


X = 4/3

P(X) = 0

P(4/3) = 0 Because 4/3 is a zero of the polynomial 6X³-11X²+KX-20.


Therefore,

P(4/3) => 0


6 × (4/3)³ - 11 × (4/3)² + K × 4/3 - 20 = 0


6 × 64/27 - 11 × 16/9 + 4K/3 - 20 = 0


2 × 64/9 - 176/9 + 4K/3 -20 = 0


128/9 - 176/9 + 4K/3 -20 = 0


128 - 176 + 12K - 180 /9 = 0


128 - 176 + 12K - 180 = 0 × 9

128 - 356 + 12K = 0

-228 + 12K = 0


12K = 228

K = 228/12


K = 19




HOPE IT WILL HELP YOU..... :-)