Question

If x = 4t3 + 2t2 5t + 6 then value of initial acceleration of the particle is :-​

Answer 1

The displacement is given as x=5t

2

+4t+3

⇒x−3=5t

2

+4t

assuming x−3=s,

s=4t+

2

1

10t

2

comparing this with s=ut+

2

1

at

2

we get u=4m/s and a=10m/s

2

so velocity at t=2sec is v=u+at=4+10×2=24m/s

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Answer 2

Answer:

Kiran Choudhary gave correct answer