Question

if x+4y+5=0 find x y​

Answer 1

Answer:

xn=y. Take the log of both sides:

logxn=logy. By identity we get:

n⋅logx=logy. Dividing both sides by log x: n=logylogx. Find the exponent of a number. ...

3n=81. Take the log of both sides:

Answer 2

Answer:

$\huge\pink{\mid{\fbox{\tt{♡ANSWER♡}}\mid}}$

x + 4y + 5 = 0

x + 4y = 0 - 5

x + 4y = -5

x = -5 - 4y

Put y = 2

x = -5 - 4(2)

x = -5 - 8

x = -13

Put x = -13 and y = 2 in the Equation

$\huge\orange{\mid{\fbox{\tt{Check:-}}\mid}}$

x + 4y + 5 = 0

-13 + 4(2) + 5 = 0

-13 + 8 + 5 = 0

-13 + 13 = 0

0 = 0

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