If x=(√5+1)/(√5-1) and y=(√5-1)/(√5+1) Find the value of x^2+y^2
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given, x = (√5 + 1)/(√5 - 1) and y = (√5 - 1)/(√5 + 1)
rationalising x and y,
x = (√5 + 1)/(√5 - 1) × (√5 + 1)/(√5 + 1)
= (√5 + 1)²/(√5² - 1²)
= (5 + 1 + 2√5)/4
= (3 + √5)/2
similarly, y = (√5 - 1)/(√5 + 1) × (√5 - 1)/(√5 - 1)
= (√5 - 1)²/(√5² - 1²)
= (5 + 1 - 2√5)/2
= (3 - √5)/2
so, x² + y² = [(3 + √5)/2]² + [(3 - √5)/2]²
= (3 + √5)²/4 + (3 - √5)²/4
= {(3 + √5)² + (3 - √5)²}/4
= {3 + 5 + 6√5 + 3 + 5 - 6√5}/4
= (3 + 5 + 3 + 5)/4
= 16/4 = 4
hence, x² + y² = 4
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See the attachment which I attached.
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