Question

If x-5,11, x+7 are consecutive term of arithmetic progression then x =

Answer 1

Step-by-step explanation:

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Write the value of x for which x+2, 2x, 2x+3 are three consecutive terms of an A.P

Medium

Solution

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Given,

x+2,2x,2x+3 are in A.P.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

The consecutive numbers are : 5+2,2(5),2(5)+3

⇒7,10,13

Answer 2

Answer:

x=10

Step-by-step explanation:

here x - 5,11,x + 7 are consecutive numbers of an AP

therefore, their common difference must be same

so,

d1 = 11 - (x - 5)

and d2 = (x + 7) - 11

therefore, d1 = d2

11 - (x - 5) = (x + 7) - 11

11 - x + 5 = x + 7 - 11

16 - x = x - 4

x + x = 16 + 4

2x = 20

x = 10