Question

if x+5, 11,x+7 are consecutive terms of an arithmetic progression then x=?​

Answer 1

Answer:

Given,

x+2,2x,2x+3 are in A.P.

⇒(2x)−(x+2)=(2x+3)−(2x)

2x−x−2=2x+3−2x

x−2=3

∴x=5

The consecutive numbers are : 5+2,2(5),2(5)+3

⇒7,10,13

Answer 2

Answer: then x= 5

Step-by-step explanation:

If x+5 , 11 , x+7 are consecutive terms of an arithmetic progression

Then, we know that,

(x+5)+(x+7) = 2×11

, 2x +12 = 22

, x = 5

The answer is x=5