Math, asked by Saleema5593, 7 hours ago

if x = (5/2) ^4 × (2/5)^-8 find the value of x^-8​

Answers

Answered by rekhadas2005
0

Answer:

x+7+4(x−5)=x+7+4x−20=x+4x+7−20

=5x−13

=5×2−13 [Putting x=2]

=10−13

=−3.

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