Math, asked by saswatasarkar955, 6 months ago

If x = √5 − √2/

√5 + √2

and xy = 1 , find the value of x2 + xy + y2

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Answers

Answered by pranabpaul102
1

Step-by-step explanation:

x²+1+y² =0

x²+y²=-1

your question is solved

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ask doubt

Answered by Anonymous
3

Step-by-step explanation:

GIVEN THAT

✓ The value of

x =  \sqrt{5}  -  \sqrt{2}

✓ The value of

y =  \sqrt{5}  +  \sqrt{2}

✓ The value of

xy = 1

TO FIND

✓ The value of

 {x}^{2}   + xy \:  +  {y}^{2}

SOLUTION

 {x}^{2}  + xy +  {y}^{2}  \\  =  {( \sqrt{5} -  \sqrt{2} ) }^{2}  + 1 +  {( \sqrt{5} +  \sqrt{2})  }^{2}  \\  =  {( \sqrt{5} )}^{2}  +  {( \sqrt{2}) }^{2}  - 2  \times  \sqrt{5}  \times  \sqrt{2}  + 1 +  {( \sqrt{5}) }^{2}  +  {( \sqrt{2} )}^{2}  + 2 \times  \sqrt{5}  \times  \sqrt{2}  \\  = 5 +   2 + 1 + 5 + 2 \\  = 15

CONCLUSION

✓ Answer:- The value of

 {x}^{2}  + xy +  {y}^{2}

= 15

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