Math, asked by UVkhurana, 6 months ago

if x=√5-2÷√5+2 and y=√5+2÷√5-2, find: xy​

Answers

Answered by VaibhavPuneet0001
1

Answer:

x = 7- 4√5 & y= 7+4√5

Step-by-step explanation:

x = (√5-2)/(√5+2)

multiplying numerator and denominator by (5-2), we get,

x = (√5-2)(√5-2)/{(√5+2)(√5-2)}

x = (√5-2)(√5-2)/{(√5+2)(√5-2)}

x = (√5-2)²/{(√5)²-(2)²}

x= [(5+2+4√5)/(5-4)].

x = (√5-2)(√5-2)/{(√5+2)(√5-2)}

x = (√5-2)²/{(√5)²-(2)²}

x= [(5+2-4√5)/(5-4)]

x = 7- 4√5

y= (5+2)/(5-2)

multiplying numerator and denominator by (√5+2), we get,

y=(5+2)²/[(5-2)(5+2)]

y= 5+2+45/{(5)²-(2)²}

y= 7+45/ ( 5-4)

y= 7+45

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