If x=√5-2/√5+2 and y=√5+2/√5-2 then show that x²-y²=-144√5
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Hey....!!! here is ur answer.....☺️☺️☺️
Here...... Given that,
x = √5–2/√5+2
& y = √5+2/√5–2
then we have to prove that.......x²–y² = –144√5
On taking L.H.S.
x²–y² = (x+y)(x–y)
{As we know that ,a²–b²=(a+b)(a–b)}
=>{(√5–2/√5+2)+(√5+2/√5–2)}{(√5–2/√5+2)–(√5+2/√5–2)}
=>{(√5–2)(√5–2)+(√5+2)(√5+2)}/5-4×
{(√5–2)(√5–2)–(√5+2)(√5+2)}/5–4
=>(5+4–4√5+5+4+4√5)/1×
{5+4–4√5–(5+4+4√5)}/1
=>(18)×(–8√5)
=>–144√5 = R.H.S. Hence proved....
I hope it may help you........✌️✌️✌️
Here...... Given that,
x = √5–2/√5+2
& y = √5+2/√5–2
then we have to prove that.......x²–y² = –144√5
On taking L.H.S.
x²–y² = (x+y)(x–y)
{As we know that ,a²–b²=(a+b)(a–b)}
=>{(√5–2/√5+2)+(√5+2/√5–2)}{(√5–2/√5+2)–(√5+2/√5–2)}
=>{(√5–2)(√5–2)+(√5+2)(√5+2)}/5-4×
{(√5–2)(√5–2)–(√5+2)(√5+2)}/5–4
=>(5+4–4√5+5+4+4√5)/1×
{5+4–4√5–(5+4+4√5)}/1
=>(18)×(–8√5)
=>–144√5 = R.H.S. Hence proved....
I hope it may help you........✌️✌️✌️
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