If X = 5 - 2√6 Find x^2+1/x^2 in brief
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identity used in finding x^2 is given below
(a-b)^2 = a^2 -2ab + b^2
now to find 1/x^2 we have to rationalise the denominator and identity used over there us given below.
(a-b) (a+b) = a^2 - b^2
Hope u can understand it now.........
(a-b)^2 = a^2 -2ab + b^2
now to find 1/x^2 we have to rationalise the denominator and identity used over there us given below.
(a-b) (a+b) = a^2 - b^2
Hope u can understand it now.........
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Kulbhushan15:
I will mark it as brainlist but plz... send me again in brief by formula I m not getting it
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Answered by
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x²+(1/x)²=(x+1/x)²-2
putting value of x... (5-2√6+1/5-2√6)²-2
[{(5-2√6)²+1}/5-2√6]-2={(25+24-20√6+1)/5-2√6}
(50-20√6-10+4√6)/5-2√6=
(54-16√6)/5-2√6=
putting value of x... (5-2√6+1/5-2√6)²-2
[{(5-2√6)²+1}/5-2√6]-2={(25+24-20√6+1)/5-2√6}
(50-20√6-10+4√6)/5-2√6=
(54-16√6)/5-2√6=
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