Math, asked by chitraksh2005p9uty2, 11 months ago

If x = 5 + 2√6
Prove that:-
√x + 1/√x = 2√3

Answers

Answered by amitraja26
1
X = 5 + 2
x = 5 + 2 \sqrt{6}



 \sqrt{x}  =  \sqrt{5 + 2 \sqrt{6} }


=.
2 \sqrt{6}  = 2 \sqrt{2 \times 3}


=
  \sqrt{} (\sqrt{3 }  +  \sqrt{2}) {}^{2}
 \sqrt{3}   +  \sqrt{2}
 1 \div  \sqrt{ \times }  =  \sqrt{3}  -  \sqrt{2}
Now


SqrtX + 1/sqrtx = 2sqrt3

chitraksh2005p9uty2: cany you tell me how 2root6 becom root(root3 + root 2 ) and where is 5
amitraja26: it can be written like this root(5 + 2root6). ROOT( 3 + 2 + 2root6). ( root3)^2 + (root2) ^2 + 2. root2. root3 ( root3 +root2) ^2. root3 + root2
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