Question

if x= 5+√2 then find x^2 - 1/x^2​

Answer 1

Step-by-step explanation:

$\frac{ {x}^{2} - 1}{ {x}^{2} }$

$\frac{( {5 + \sqrt{2} )}^{2} - 1}{ ({5 + \sqrt{2} )}^{2} }$

$\frac{25 + 2 - 1}{25 + 2}$

$\frac{26}{27}$

Answer 2

Answer:

if x= 5+√2 then x^2 - 1/x^2 is equal to

x^2 - 1/x^2=(5+√2)^2-1/(5+√2)^2

x^2 - 1/x^2=[(27-10√2)(27-10√2)-1]\(5+√2)^2