Question

if x = 5-√21/2, find the value of
xpower 2 + 1/ xpower 2
​

Answer 1

Answer:

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Step-by-step explanation:

Varun have a total of Rs 500 in coins of denomination rupee 1, rupee 2 and rupee 5. The number of rupee 1 coins is twice the number of rupee 2 coins. The total number of coins is 210. How many coins of each denomination does Varun have?

Answer 2

Answer:

x = 5-√21/2

x² = (5-√21/2)²

= 25-21/4

= 4/4 = 1

1/x² = 1/(5-√21/2)²

= 1/(25-21/4)

= 4/25-21

= 4/4 = 1

x²+1/x² = 1²+1² = 2

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