If x = 5 -2V6 , find x² +1/x?
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If x=1/(x-5), where x is not equal to 5, what will be the value of x²-(1/x²)?
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x=1/x-5 is not equal to 5
x^2 --(1/x^2)
1/ (x-5)^2 -- 1/1 (x-5)^2
=(1 --( x-5)^4)/ (x--5)^2
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x=1/(x-5)
Or x-5=1/x since x is not equal to zero
Or x-1/x=5 ………(1)
Squaring both sides
(x-1/x)^2=25
Or x^2–2×x×(1/x)+1/(x^2)=25
Or x^2–2+1/(x^2)=25
Or x^2+1/(x^2)=25+2=27
Adding 2 to both sides we have
x^2+2+1/(x^2)=29
Or x^2+2×x×(1/x)+1/(x^2)=29
Or (x+1/x)^2=29
Or x+1/x=+-(29)^(1/2)………(2)
Multiplying (1) and (2) we have
x^2–1/x^2=+-5×(29)^(1/2)
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