if x^5+2x^4+35 is divided by x-1 find the remainder
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Answered by
1
the answer is 38
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#Hassan
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babluyadav89:
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aise kar sakte hai
Answered by
0
2 methods - first is long division by (x+2)
(x+2),2nd is to us remainder theorem
let f(x)=4x2+2kx-5
f(x)=4x2kx-5
And g(x)=x+2
g
(
x
)
=
x
+
2
to find the remainder of f(x)g(x)
f
(
x
)
g
(
x
)
where g(x)=(x+c)
g
(
x
)
=
(
x
+
c
)
we need to evaluate f(−c)
f
(
−
c
)
f(−2)=4(−2)2+2k(−2)−5
f
(
−
2
)
=
4
(
−
2
)
2
+
2
k
(
−
2
)
−
5
Because the remainder is 3, we know that f(−2)=3
f
(
−
2
)
=
3
so
16−4k−5=3
16
−
4
k
−
5
=
3
4k=8
4
k
=
8
k=2
k
=
2
is that correct?
mine is correct
Well hmmmmm HMMMMMM
ill have to think a bit
apana number bejo us pat main answer beju
Umm what
i can’t find the answer sorrrrry
@namrata whether it is written in the question that you have to answer this question only by xyz method?
just great
I’m trying to calculate but I’m not doing the correct answer
well its ok
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