if X=5-3√3. find (i) x^2+1/x (ii) (x^3-1/x^3) (iii) ( x-1/x)
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Given:-
X=5-3√3
To Find:-
(i) x^2+1/x
= (5-3√3)^2 + 1/5-3√3
= 25-27 + 1/5-3√3
= -2 + 1/5-3√3
= (-2(5-3√3) + 1)/5-3√3
=-10-6√3 + 1/5-3√3
Multiply √3 in numerator and denominator
we get;
= 10√3-18 - 1/5-9
= 10√3-17/-4✔️
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