if x=5+3√3 then find the value of x2+1/x2
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★Answer★
______________________________
Given,
x=5+3√3
→ 1/x =1/5+3√3
→ 1/x = 1 × (5-3√3) / (5+3√3)(5-3√3)
→ 1/x = 5 - 3√3 / (5)^2 - (9×3)
→ 1/x = 5 - 3√3 / 25 - 27
→ 1/x = 5 - 3√3 / -2
Now,
x+1/x
= (5 + 3√3) + 5 - 3√3/-2
= -10 - 6√3 -5 + 3√3
=-15 - 6√3
=if x=5+3√3 then find the value of x2+1/x2
So,
x^2 + 1/x^2
=(x+1/x)^2 - 2. x . 1/x
={(-15 -6√3)^2} - 2 . (5+3√3) . (-15 - 6√3)
={(-15)^2 - 2. -15 . 6√3 + (6√3)^2}
- 2(-75 - 30√3 - 45 √3 - 54)
=225-180√3+108+150+60√3+90√3+108
=591 - 30√3
so, x^2 + 1/x^2 = 591-30√3
_______________________________
#Hope Helped (:
★Answer★
______________________________
Given,
x=5+3√3
→ 1/x =1/5+3√3
→ 1/x = 1 × (5-3√3) / (5+3√3)(5-3√3)
→ 1/x = 5 - 3√3 / (5)^2 - (9×3)
→ 1/x = 5 - 3√3 / 25 - 27
→ 1/x = 5 - 3√3 / -2
Now,
x+1/x
= (5 + 3√3) + 5 - 3√3/-2
= -10 - 6√3 -5 + 3√3
=-15 - 6√3
=if x=5+3√3 then find the value of x2+1/x2
So,
x^2 + 1/x^2
=(x+1/x)^2 - 2. x . 1/x
={(-15 -6√3)^2} - 2 . (5+3√3) . (-15 - 6√3)
={(-15)^2 - 2. -15 . 6√3 + (6√3)^2}
- 2(-75 - 30√3 - 45 √3 - 54)
=225-180√3+108+150+60√3+90√3+108
=591 - 30√3
so, x^2 + 1/x^2 = 591-30√3
_______________________________
#Hope Helped (:
Anonymous:
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