Question

If (x + 5) and (x – 3) are the factors of ax² + bx + c, then values of a, b and c are ​

Answer 1

Answer:

Given that (x+5) and (x-3) are the factors of the the equation,

then, (x+5)(x-3)=0

         x+5=0  ;  x-3=0

          ⇒x=(-5),3

LET, α=(-5);β=3

α+β=(-5)+3=(-2)

αβ=(-5)×3=(-15)

Now,

→ax²+bx+c=k(x²-(α+β)x+αβ)

→ax²+bx+c=k(x²-(-2)x+(-15))

→ax²+bx+c=k(x²+2x-15)

→ax²+bx+c=x²+2x-15      (∵k is constant)

by equating the coefficients we get,

⇒a=1

⇒b=2

⇒c=(-15)

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Hope it helps u........

Answer 2

Step-by-step explanation:

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