Question

if x= 5 and y= 2, find the value of (x^y + y^x)^-1 and (x^x + y^y)^1

Answer 1

Step-by-step explanation:

(x^y + y^x)^-1

=(5^2+2^5)^-1=(25+32)^-1=1/57

(x^x + y^y)^1

(5^5+2^2)^1=(3125+4)^1=(3129)^1=3129