Question

if x=5 and y=2 then, find the value of 1. (x^y+y^x)^-1 2. (x^x+y^y)^-1​

Answer 1

Step-by-step explanation:

here x is 5 and y is 2

so it will be

1. (5×2 + 2×5) - 1

20-1

19

2. (5×5 + 2×2) - 1

25+4 -1

29-1

28

please mark as brainliest

Answer 2

Answer:

It’s very simple ! Just replace “x” and “y” with the numbers given, then do it as normal. I think this math problem isn’t serious at all

(x + y)^2

= (5 + 2)^2

There are many ways to solve this step and many ways to understand:

(1):

= 7^2

= 7 x 7

= 49

(2):

= (5 + 2) x (5 + 2) // exponentiation is just the multiply operation between those numbers which are the same as each other //

= 7 x 7 // and we still follow the “operation rules” in Math, prioritize for brackets (solving first) → multiply / divide → add / substract //

= 49

You must solve for anything in the brackets first, this’s the best way for this math problem !

But if you want to prove that whether this is right or you don’t know why / believe in these math rules, you can apply “binomial theorem” ( see more: ). But this is just a suggestion, I think it’s more complex! xD haha

(a + b)^2 = a^2 + 2ab + b^2

As for your math problem, (x + y)^2 = x^2 + 2xy + y^2

Still, we must replace x = 5 and y = 2 to find out the last result

→ 5^2 + 2 x 5 x 2 + 2^2

= 25 + 20 + 4

= 49

or:

(x + y)^2 = (5 + 2)^2 // just different from the step which we replace x = 5 and y = 2 first then we apply the binomial theorem //

= … (as the way above)

Finally, your answer is (x + y)^2 with x = 5 and y = 2 is 49

Step-by-step explanation:

I hope its help to you