Math, asked by teeshapanchalteesha, 1 year ago

if x=5 and y=2 then find the value of (x^x + y^y )^-1​

Answers

Answered by sharanyacs1306
22

Answer:

On substituting the value x = 5 and y = 2 in

(x × x + y × y ) × -1

( 5 × 5 + 2 × 2 ) × -1

( 25 + 4 ) × -1

(29) × -1

-29

Answered by chaudharyvikramc39sl
2

Answer:

\frac{1}{3129}=0.0003195

Step-by-step explanation:

Given Expression :

                   (x^x+y^y)^{-1}

To find :

Value of the expression on x=5 and y=2.

Solution :

Substituting the value of x and y in the above expression we get

               =    (5^5+2^2)^{-1}

               =   (3125+4)^{-1}

               =   \frac{1}{3129}

               =   0.0003195

Hence the value of the Expression = 0.0003195 .

#SPJ2

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