Question

If x=5 and y=4 , then prove that (x=y)^2=x^2+2xy+y^2

Answer 1

Answer:

Proved: $(x+y)^{2}=x^{2}+2xy+y^{2}$

Step-by-step explanation:

It is provided that x = 5 and y = 4.

To prove: $(x+y)^{2}=x^{2}+2xy+y^{2}$

Consider the RHS:

$x^{2}+2xy+y^{2}=(5)^{2}+(2\times5\times4)+(4)^{2}=25+40+16=81$

Consider the LHS:

$(x+y)^{2}=(5+4)^{2}=9^{2}=81$

LSH = RHS

Hence proved.