if x+5 is a factor of p(x)=2x^3+3x^2+4x+k,find the value of k
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Answered by
1
REPLACE P(X) BY -5
THE YOU WILL GET
P(-5)=2(-5)^3+3(-5)^2+4(-5)+k=0
240+75-20+K=0
K=-295
Answered by
1
g(x)=x+5
p(x)=2x^3+3x^2+4x+k
g(x)=0
x+5=0
x=-5
p(-5)=0
2x^3+3x^2+4x+k=0
2(-5)^3+3(-5)^2+4(-5)+k=0
2(-125)+3(25)-20+k=0
-250+75-20+k=0
-175-20+k=0
-195+k=0
k=195
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