If x+5 is a factor x^2+kx+5 then find the value of k please
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Answered by
1
zero of x+5= -5
p(x)= x²+kx+5
we know that x+5 is a factor of p(x)
so, p(x)= x²+kx+5
p(-5)= (-5)² +k(-5)+5=0
25-5k+5=0
30-5k=0
-5k=-30
k=6
p(x)= x²+kx+5
we know that x+5 is a factor of p(x)
so, p(x)= x²+kx+5
p(-5)= (-5)² +k(-5)+5=0
25-5k+5=0
30-5k=0
-5k=-30
k=6
Answered by
0
Since x+5 is a factor of x^2+kx+5,
x^2+kx+5 = 0 (for x = -5)
=> (-5)^2 - 5k + 5 = 0
=> - 5k = - 30
=> k = 6
Therefore, k = 6
x^2+kx+5 = 0 (for x = -5)
=> (-5)^2 - 5k + 5 = 0
=> - 5k = - 30
=> k = 6
Therefore, k = 6
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