Question

If x + 5 is a number that is completely divisible by 13, which of those numbers will be completely divisible by 26?
a. x+26
b. 2x + 36
c. 2x + 5
d. 2x +13​

Answer 1

Given info : If x + 5 is a number that is completely divisible by 13.

To find : which of those numbers will be completely divisible by 26.

a. x + 26

b. 2x + 36

c. 2x + 5

d. 2x + 13

solution : x + 5 is a number which is divisible by 13.

so, we can write x + 5 in the multiple of 13, right ?

i.e., x + 5 = 13k , where k is natural number.

now, 2(x + 5) = 2 × 13k

⇒2x + 10 = 26k

⇒(2x + 10) + 26 = 26k + 26

⇒2x + 36 = 26(k + 1)

here it is clear that 2x + 36 is multiple of 26. it means, 2x + 36 is completely divisible by 26.

Therefore the correct choice is option (b) 2x + 36.

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Answer 2

Step-by-step explanation:

Given info: If x + 5 is a number that is

completely divisible by 13.

To find which of those numbers will be completely divisible by 26.

a. x + 26

b. 2x + 36

c. 2x + 5

d. 2x + 13

solution : x + 5 is a number which is divisible by 13.

so, we can write x + 5 in the multiple of 13,

right?

i.e., x + 5 = 13k, where k is natural number.

now, 2(x + 5) = 2 × 13k

⇒2x + 10 = 26k

⇒(2x+10) + 26 = 26k + 26

⇒2x + 36 = 26(k + 1)

here it is clear that 2x + 36 is multiple of 26. it means, 2x + 36 is completely divisible by 26.

Therefore correct choice is option (b) 2x +

36.

also read similar questions: By actual division, find the quotient and the remainder when the

first polynomial is

divided by the second polynomial:...