Question

If X=5 is a root of equation kx²-14x-5=0 what is value of k ? *​

Answer 1

Answer:

$x = 5 \\ p(x) =k {x}^{2} - 14x - 5 \\ k {x}^{2} - 14x - 5 = 0 \\ k ({5})^{2} - 14(5) - 5 = 0 \\ k(25) - 70 - 5 = 0 \\ 25k - 75 = 0 \\ 25k = 75 \\ k = \frac{75}{25} \\ \purple{ \fbox{ \red{k = 3}}}$

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Answer 2

Answer:

k=3 is the answer to this question